在通过双水音箱的全双重水下声学通信中取消自我干扰
Songwen Wu1,2,3,4, Yinheng Lu5, Feng Zhou1,2,3,4
1National Key Laboratory of Underwater Acoustic Technology, Harbin Engineering University, Harbin 150001, China.
The Journal of the Acoustical Society of America
|December 30, 2025
概括
本研究介绍了一种全双重 (FD) 水下声通信 (UWAC) 系统的新型自我干扰取消 (SIC) 方法. 该技术有效减少干扰,使得水下数据传输更清晰,远距离.
科学领域:
- 水下声学通讯水下声学通讯
- 信号处理 信号处理
- 无线通信系统无线通信系统
背景情况:
- 强烈的自我干扰 (SI) 是全双重 (FD) 水下声通信 (UWAC) 系统的一个主要挑战.
- 现有的自我干扰取消 (SIC) 方法在与非线性干扰和未知干扰源作斗争.
研究的目的:
- 为FD-UWAC系统提出和验证一个先进的SIC方法.
- 解决传统SIC技术的局限性,特别是在处理强大的SI和非线性干扰方面.
- 提高水下声通信的稳定性和性能.
主要方法:
- 开发了一种先进的SIC方法,利用两个水声机之间的差分通道特征.
- 在距离源更近的参考水声机上使用,以取消远处接收器的SI.
- 实现了SIC模型通道参数的动态更新,以实现稳定的性能.
- 通过游泳池实验和海上试验验证了该方法.
主要成果:
- 在池实验中,SIC性能大约达到54.75dB.
- 远端信号的位误差率保持在1 × 10-3以下.
- 在海上试验中证明了50公里的浅海通信,信号干扰比为-40dB.
- 与传统方法相比,它展示了优越的SIC能力,特别是在非线性和未知干扰方面.
结论:
- 拟议的SIC方法为FD-UWAC系统中的自我干扰取消提供了一个强大的解决方案.
- 该技术为增强水下通信能力提供了重要的理论和实践价值.
- 动态适应和优异的干扰处理使这种方法对现实世界的应用具有前景.
相关概念视频
Sound Waves: Interference
4.5K
Sound waves can be modeled either as longitudinal waves, wherein the molecules of the medium oscillate around an equilibrium position, or as pressure waves. When two identical waves from the same source superimpose on each other, the combination of two crests or two troughs results in amplitude reinforcement known as constructive interference. If two identical waves, that are initially in phase, become out of phase because of different path lengths, the combination of crests with troughs...
4.5K
Interference: Path Lengths
1.8K
Consider two sources of sound, that may or may not be in phase, emitting waves at a single frequency, and consider the frequencies to be the same.
Two special sources may be considered when they are in phase. This can be easily achieved by feeding the two sources from the same source. An example would be synchronizing the two speakers by feeding them with the same source, such as the sound waves produced by a tuning fork. This setup ensures that the two sources have the same frequency and are...
Two special sources may be considered when they are in phase. This can be easily achieved by feeding the two sources from the same source. An example would be synchronizing the two speakers by feeding them with the same source, such as the sound waves produced by a tuning fork. This setup ensures that the two sources have the same frequency and are...
1.8K
Echo
846
The human ear cannot distinguish between two sources of sound if they happen to reach within a specific time interval, typically 0.1 seconds apart. More than this, and they are perceived as separate sources.
Imagine the sound is reflected back to the ears. Assuming that the source is very close to the human, the difference between hearing the two sounds—the emitted sound and the reflected sound—may be more than the minimum time for perceiving distinct sounds. If this is the case,...
Imagine the sound is reflected back to the ears. Assuming that the source is very close to the human, the difference between hearing the two sounds—the emitted sound and the reflected sound—may be more than the minimum time for perceiving distinct sounds. If this is the case,...
846
Interference and Superposition of Waves
6.3K
When two waves of the same nature occur in the same region simultaneously, they result in interference. Interference of waves implies that the net effect of the waves is the sum of the individual waves' effects. However, it does not imply that the individual waves affect the propagation of other waves.
Interference occurs in mechanical waves, such as sound waves, waves on a string, and surface water waves. Mechanical waves correspond to the physical displacement of particles. Hence,...
Interference occurs in mechanical waves, such as sound waves, waves on a string, and surface water waves. Mechanical waves correspond to the physical displacement of particles. Hence,...
6.3K
Uniform Depth Channel Flow: Problem Solving
414
To calculate the flow rate for a trapezoidal channel, first, identify the bottom width, side slope, and flow depth of the channel. The cross-sectional area (A) corresponding to the depth of flow (y), channel bottom width (B), and side slope (θ) is determined by:Next, calculate the wetted perimeter, which includes the bottom width and the sloped side lengths in contact with the water. Using the values of the cross-sectional area and the wetted perimeter, determine the hydraulic radius by...
414


