2 - 甲基烯酸和化之间的反应产生的两个不同的产物:化与二聚相比:化
James P Chakiris1, Christopher J Sumby2, Douglas A Brooks1
1Clinical and Health Sciences, University of South Australia, Adelaide, South Australia, 5000, Australia.
Acta crystallographica. Section C, Structural chemistry
|January 7, 2026
概括
化和2-甲基烯酸的反应产生了基于溶剂的不同产品. 水会产生酸 5,而乙醇会产生二聚 6,这对先前的文献提出了挑战.
科学领域:
- 有机化学 有机化学
- 超分子化学 超分子化学
- 晶体学 晶体学是指结晶学.
背景情况:
- 异环化合物的合成通常涉及与酸的反应.
- 文献报告表明,化和2-甲酸的反应产生的特定产物.
研究的目的:
- 在不同的溶剂条件下研究化和2-甲基烯酸的反应产物.
- 用光谱和晶体学方法来表征获得的化合物.
- 澄清与现有文献有关反应结果的差异.
主要方法:
- 化与水和乙醇中的2 - 甲基烯酸的反应.
- 使用NMR光谱 (1H, 13C, 11B),高分辨率质谱法 (HRMS) 的表征.
- 单晶X射线衍射用于两种产品的结构确定.
主要成果:
- 在水中的反应产生了醇化 5 ((E) -{2-[(2-醇化) 甲基]基}酸).
- 在乙醇中的反应仅产生了二元体6 ({oxybis[benzo[d][2,3,1]diazaborinine-1,2(1H) -diyl]}bis(phenylmethanone)).
- X射线衍射揭示了不同的固态结构,包括5个分子内键和6个具有B-O定性键的双循环系统.
结论:
- 反应结果高度依赖于使用的溶剂.
- 这项研究提供了明确的证据,证明了醇化5或二聚6的形成,这与之前的文献相矛盾.
- 结构分析强调了键和dative键在产品形成和稳定性中的作用.
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