同质性对参考材料稳定性评估的影响
Kalman Toth1, Thomas P J Linsinger1
1European Commission, Joint Research Centre, Retieseweg 111, Geel, 2440, Belgium.
Analytica chimica acta
|January 12, 2026
概括
估计认证参考材料 (CRM) 的稳定性不确定性至关重要. 使用线性混合效应模型 (LME) 准确计算这种不确定性,即使有物质变化,避免来自普通最小方程方法的偏差.
科学领域:
- 计量学 计量学 计量学
- 分析化学 分析化学
- 统计 统计 统计 统计
背景情况:
- 准确的不确定性估计对于认证参考材料 (CRM) 来说至关重要.
- 在CRM中单元间的异质性可能会偏向使用普通最小平方的不确定性计算.
- 这种偏差受到材料异质性,方法可重复性和复制数量的影响.
研究的目的:
- 调查CRM中单位间异质性引起的稳定性不确定性估计偏差.
- 评估线性混合效应模型 (LME) 在解决这种偏差方面的有效性.
- 为特定的数据场景提供替代方法.
主要方法:
- 应用线性混合效应模型 (LME) 与限制最大概率 (REML) 进行参数估计.
- 对实际认证值的分析,以评估偏差影响.
- 将LME与普通最小平方方法进行比较.
主要成果:
- 普通最小方程方法在稳定性不确定性估计中引入了显著的偏差 (高达50%),具有单位间异质性.
- 线性混合效应模型 (LME) 提供一致且公正的不确定性估计.
- 来自普通最小平方的偏差可以影响经过认证的值.
结论:
- 建议使用线性混合效应模型 (LME) 来准确估计在CRM中具有单元间异质性的稳定性不确定性.
- 为平衡数据集提供了更简单的替代方法.
- 适当的统计方法对于可靠的CRM表征至关重要.
相关概念视频
Test for Homogeneity
2.4K
The goodness–of–fit test can be used to decide whether a population fits a given distribution, but it will not suffice to decide whether two populations follow the same unknown distribution. A different test, called the test for homogeneity, can be used to conclude whether two populations have the same distribution. To calculate the test statistic for a test for homogeneity, follow the same procedure as with the test of independence. The hypotheses for the test for homogeneity can...
2.4K
Data Validation
568
Method validation is a crucial process in analytical chemistry designed to confirm that a given method consistently produces reliable and high-quality results. This process is essential when a method is applied to different sample matrices or when procedural modifications are made, ensuring that the results meet acceptable standards across various applications.
Key parameters for method validation include:
Key parameters for method validation include:
568
Stability of structures
450
In mechanical engineering, the stability of systems under various forces is critical for designing durable and efficient structures. One fundamental way to explore these concepts is by analyzing systems like two rods connected at a pivot point, O, with a torsional spring of spring constant k at the pivot point. This system is similar in appearance to a scissor jack used to change tires on a car. In this case, the arms of the linkage (equivalent to the rods in this system) are entirely vertical,...
450
Stability of Substituted Cyclohexanes
14.7K
This lesson discusses the stability of substituted cyclohexanes with a focus on energies of various conformers and the effect of 1,3-diaxial interactions.
The two chair conformations of cyclohexanes undergo rapid interconversion at room temperature. Both forms have identical energies and stabilities, each comprising equal amounts of the equilibrium mixture. Replacing a hydrogen atom with a functional group makes the two conformations energetically non-equivalent.
For example, in...
The two chair conformations of cyclohexanes undergo rapid interconversion at room temperature. Both forms have identical energies and stabilities, each comprising equal amounts of the equilibrium mixture. Replacing a hydrogen atom with a functional group makes the two conformations energetically non-equivalent.
For example, in...
14.7K
Pharmaceutical Alternatives: Stability-Related Therapeutic Nonequivalence
177
Generic intravenous (IV) drugs are considered bioequivalent to their branded counterparts due to their 100% bioavailability upon administration. However, variations in stability among different drug products can significantly influence their therapeutic performance, even if they are pharmaceutically equivalent.Cefuroxime, a prophylactic antimicrobial, is often used as a single-dose IV injection for patients undergoing coronary artery bypass grafting surgery. A 3 g dose typically provides...
177
Propagation of Uncertainty from Systematic Error
1.3K
The atomic mass of an element varies due to the relative ratio of its isotopes. A sample's relative proportion of oxygen isotopes influences its average atomic mass. For instance, if we were to measure the atomic mass of oxygen from a sample, the mass would be a weighted average of the isotopic masses of oxygen in that sample. Since a single sample is not likely to perfectly reflect the true atomic mass of oxygen for all the molecules of oxygen on Earth, the mass we obtain from this...
1.3K


