相关实验视频
Updated: Feb 14, 2026

08:04
Conditions Affecting Social Space in Drosophila melanogaster
Published on: November 5, 2015
12.9K
研究恒星传感器成像模拟在近太空高超音速非平衡流量条件下的研究
Zhen Liao1, Hongyuan Wang1, Xi Cheng1
1Research Center of Space Optical Engineering, Harbin Institute of Technology, Harbin 150001, China.
Sensors (Basel, Switzerland)
|February 13, 2026
概括
这项研究开发了一个模拟模型,用于超音速条件下的恒星传感器成像. 该模型显示,固体介质辐射显著降低了恒星传感器图像,影响了近太空平台的性能.
科学领域:
- 航空航天工程 航空航天工程
- 光学工程是指光学工程.
- 天体动力学是指天体动力学.
背景情况:
- 恒星传感器对于太空导航至关重要.
- 超音速飞行条件给成像系统带来了重大挑战.
- 退化的恒星传感器图像阻碍了准确的态度确定.
研究的目的:
- 开发一个模拟模型用于超音速条件下的恒星传感器成像.
- 分析热化学非平衡流对恒星传感器性能的影响.
- 为超音速平台上的恒星传感器设计提供理论支持.
主要方法:
- 采用了超音速非平衡流动的两个温度模型.
- 模拟化学反应使用阿雷尼乌斯定律.
- 量化分析光学传输和热辐射效应.
- 在典型的工作条件下模拟退化恒星图像.
主要成果:
- 热化学非平衡流量显著降低了恒星传感器图像.
- 来自固体介质的辐射被确定为主要的降解因子.
- 在测试条件下,可检测极限值被确定为3.28和4.55.
结论:
- 开发的模型有效地模拟了超音速条件下的恒星传感器退化.
- 固体介质辐射是影响恒星传感器成像的关键因素.
- 结果为设计和测试用于近太空高超音速应用的恒星传感器提供了重要支持.
相关概念视频
Conditions of Equilibrium
2.2K
Equilibrium refers to a state where a rigid body is not subjected to any translational or rotational motion. This state is achieved when the force and couple acting on a rigid body equal zero. When the system of external forces results in a net effect equivalent to zero, the rigid body is considered to be in equilibrium.
Internal forces are not considered for conditions of equilibrium because they occur in equal and opposite pairs within the body, effectively canceling each other. As a result,...
Internal forces are not considered for conditions of equilibrium because they occur in equal and opposite pairs within the body, effectively canceling each other. As a result,...
2.2K
Equilibrium Conditions for a Particle
2.3K
When an object is in equilibrium, it is either at rest or moving with a constant velocity. There are two types of equilibrium: static and dynamic. Static equilibrium occurs when an object is at rest, while dynamic equilibrium occurs when an object is moving with a constant velocity. In both cases, there must be a balance of forces acting on the object.
To understand the concept of equilibrium, let us first consider the forces acting on an object. When different forces act on an object, they can...
To understand the concept of equilibrium, let us first consider the forces acting on an object. When different forces act on an object, they can...
2.3K
Dynamic Equilibrium
63.5K
A reversible chemical reaction represents a chemical process that proceeds in both forward (left to right) and reverse (right to left) directions. When the rates of the forward and reverse reactions are equal, the concentrations of the reactant and product species remain constant over time and the system is at equilibrium. A special double arrow is used to emphasize the reversible nature of the reaction. The relative concentrations of reactants and products in equilibrium systems vary greatly;...
63.5K
Free Energy and Equilibrium
27.4K
The free energy change for a process may be viewed as a measure of its driving force. A negative value for ΔG represents a driving force for the process in the forward direction, while a positive value represents a driving force for the process in the reverse direction. When ΔGrxn is zero, the forward and reverse driving forces are equal, and the process occurs in both directions at the same rate (the system is at equilibrium).
Recall that Q is the numerical value of the mass action...
Recall that Q is the numerical value of the mass action...
27.4K
Calculating Equilibrium Concentrations
53.9K
Being able to calculate equilibrium concentrations is essential to many areas of science and technology—for example, in the formulation and dosing of pharmaceutical products. After a drug is ingested or injected, it is typically involved in several chemical equilibria that affect its ultimate concentration in the body system of interest. Knowledge of the quantitative aspects of these equilibria is required to compute a dosage amount that will solicit the desired therapeutic effect.
A more...
A more...
53.9K
Calculating the Equilibrium Constant
38.3K
The equilibrium constant for a reaction is calculated from the equilibrium concentrations (or pressures) of its reactants and products. If these concentrations are known, the calculation simply involves their substitution into the Kc expression.
For example, gaseous nitrogen dioxide forms dinitrogen tetroxide according to this equation:
For example, gaseous nitrogen dioxide forms dinitrogen tetroxide according to this equation:
38.3K

