精密应力工程在度灵感的纳米架构中,可以通过尺寸影响的收缩来实现
Amitha R Mulastham1, Caelan Wisont1, Robert Verdoes1
1Mechanical Engineering, University of Washington, Seattle, WA, United States.
Small (Weinheim an der Bergstrasse, Germany)
|February 26, 2026
概括
研究人员通过控制热解过程中的聚合物收缩来开发纳米密度. 这种方法精确地将3D残余应力编程成纳米尺度的超材料,提高了硬度的2.5倍.
科学领域:
- 材料科学 材料科学 材料科学
- 机械工程 机械工程
- 纳米技术 纳米技术
背景情况:
- 余应力网络可以增强材料的性能,但纳米控制是困难的.
- 张向性结构通过紧张元件网络中的孤立压缩元件提供了独特的机械优势.
研究的目的:
- 开发一种方法来创建预压缩的紧密度启发的纳米架构 (纳米紧密度).
- 研究聚合物在热解过程中的尺寸依赖性收缩及其在制造残余应力中的应用.
- 为了证明精确控制纳米级的3D残余应力,以获得可调节的机械性能.
主要方法:
- 在热解过程中利用受尺寸影响的聚合物收缩现象.
- 使用双光子光刻法制造不同尺寸的聚合物前体.
- 热解聚合物结构以创建预应力玻璃碳纳米密度.
- 使用综合实验验证和数值建模.
主要成果:
- 发现了基于烯酸盐的聚合物在热解过程中缩小尺寸的电力定律依赖性,与剩余的氧基有关.
- 成功制造了预应力玻璃碳纳米密度,预应力可以通过条与肌直径的比率来控制.
- 由于被编程的预压力,度增加了多达两倍半.
- 在过度应力下识别了细节的曲极限,并分析了建筑对预应力效应的效应.
结论:
- 建立了一种新的方法,可以精确地在纳米尺度上将3D残余应力编程成元材料.
- 能够创建一个新的类型的机械调节的纳米架构与增强的刚性.
- 这些发现为设计具有定制机械反应的先进纳米级材料开辟了道路.
更多相关视频
相关概念视频
Shrinkage in Concrete
448
Shrinkage in concrete is primarily due to water loss from evaporation, hydration of cement, or carbonation, leading to a reduction in volume. The volumetric contraction results in volumetric strain in concrete. However, in practice, shrinkage is measured as linear strain, which is one-third of the volumetric strain.
When concrete is still in its plastic state, it can undergo a decrease in volume by about 1% of its absolute volume. This decrease is known as plastic shrinkage. It arises either...
When concrete is still in its plastic state, it can undergo a decrease in volume by about 1% of its absolute volume. This decrease is known as plastic shrinkage. It arises either...
448
Elastic Strain Energy for Shearing Stresses
555
As discussed in previous lessons, strain energy in a material is the energy stored when it is elastically deformed, a concept crucial in materials science and mechanical engineering. This energy results from the internal work done against the cohesive forces within the material. When a material undergoes shearing stress and corresponding shearing strain, the strain energy density, which is the energy stored per unit volume, is calculated. Within the elastic limit, where the stress is...
555
Elastic Strain Energy for Normal Stresses
645
Strain energy quantifies the energy stored within a material due to deformation under loading conditions, a fundamental concept in materials science and engineering. The strain energy can be modeled when a material is subjected to axial loading with uniformly distributed stress. In this scenario, the stress experienced by the material is the internal force divided by the cross-sectional area, and the strain induced is directly proportional to this stress through the modulus of elasticity.
If...
If...
645
True Stress and True Strain
899
Engineering stress is calculated as the load divided by the original, undeformed cross-sectional area. It approximates a material under load. This approximation is especially relevant post-yield in ductile materials. Though engineering stress-strain diagrams are often used for their convenience and accessibility, they can sometimes fall short in accuracy, particularly when dealing with large strain values.
In contrast, true stress offers a more precise portrayal. It is computed by dividing the...
In contrast, true stress offers a more precise portrayal. It is computed by dividing the...
899
Relation between Poisson's ratio, Modulus of Elasticity and Modulus of Rigidity
647
Deformation occurs in axial and transverse directions when an axial load is applied to a slender bar. This deformation impacts the cubic element within the bar, transforming it into either a rectangular parallelepiped or a rhombus, contingent on its orientation. This transformation process induces shearing strain. Axial loading elicits both shearing and normal strains. Applying an axial load instigates equal normal and shearing stresses on elements oriented at a 45° angle to the load axis.
647
Residual Stresses
705
Residual stresses reside in a structure even after removing the original stress inducer. This phenomenon often arises from varied plastic deformations across different parts of a structure. Consider a rod stretched beyond its yield point. It will not regain its original length due to permanent deformation. Even after load removal, the rod does not entirely lose stress because of uneven plastic deformations, resulting in residual stresses. The computation of these stresses in structures is...
705


