在破碎的多孔介质中普遍透值混合法:统一形状和尺寸多分散性和尺寸性合
Hui Yuan1, Huisu Chen1, Mingqi Li2
1Southeast University, State Key Laboratory of Engineering Materials for Major Infrastructure, School of Materials Science and Engineering, Nanjing, 211189, China.
Physical review letters
|March 13, 2026
概括
我们为3D孔和2D断裂的混合网络开发了一个新的混合规律,可以更好地预测复杂的断裂多孔介质中的流体流动,并指导材料设计.
科学领域:
- 多相流在多孔介质中的多相流.
- 计算流体动力学 计算流体动力学
- 材料科学是一种材料科学.
背景情况:
- 在破裂的多孔介质中透是复杂的,这是由于合的孔-断裂连接性.
- 现有的模型与混合维度和多种各样的孔隙和骨折形状作斗争.
- 了解这些系统对于地下水文学和材料设计至关重要.
研究的目的:
- 为 3D 孔和 2D 断裂的混合网络得出统一的混合规律.
- 为了考虑到这些网络中尺寸和形状的多分散性.
- 将理论理解与实际工程应用相结合.
主要方法:
- 对于重叠的3D超体 (孔隙) 和2D超体 (骨折) 的混合定律的推导.
- 包含单体和多体系统 (R_{eqp}=R_{eqf}和R_{eqp,max}=R_{eqf,max}) 的等价半径条件.
- 在各种维度的数值模拟和现有文献数据的验证.
主要成果:
- 建立了适用于混合维度多孔介质的新混合法.
- 该定律成功地预测了各种孔隙和断裂几何形状的系统中的透行为.
- 确定了多分布合中的相互依赖.
结论:
- 衍生出的混合定律为分析复杂的破裂多孔介质中的流体流动提供了强大的框架.
- 这项工作使得在地表水文学和纳米复合材料设计中的应用程序的形态目标优化成为可能.
- 它在理解和建模多维系统方面提供了显著的进步.
相关概念视频
Uniform Depth Channel Flow
709
Uniform depth channel flow keeps fluid depth consistent along channels such as irrigation canals. In natural channels, such as rivers, approximate uniform flow is often assumed. This condition occurs when the channel’s bottom slope matches the energy slope, balancing potential energy lost from gravity with head loss due to shear stress. This balance prevents depth changes along the channel length, resulting in a steady, uniform flow.Uniform flow in open channels with a constant cross-section...
709
Permeability of Concrete
586
Permeability in the context of concrete refers to how easily liquids or gases can pass through the material. This quality is crucial for assessing the water-tightness and durability of concrete structures and their resistance to chemical attacks. Concrete permeability can be determined through comparative laboratory tests. These tests typically involve sealing a concrete specimen from the sides, applying water pressure to the top surface with pressure, and measuring the amount of water passing...
586
The Thermodynamics of Mixing
52
Mixing is a fascinating phenomenon in thermodynamics, particularly when considering the Gibbs energy of a mixture at constant temperature and pressure. This energy, denoted as G, tends to decrease during spontaneous mixing processes, offering insights into the composition changes that occur.Imagine two ideal gases, initially separated in different containers, with amounts nA and nB, respectively, both at a temperature T and pressure p. The chemical potentials of these gases have their 'pure'...
52
Major Losses in Pipes
2.3K
When a fluid flows through a pipe, it experiences energy losses due to frictional resistance along the pipe walls, known as major losses. These energy losses result in a pressure drop, which varies based on the flow conditions — whether laminar or turbulent — and the specific physical properties of the fluid and pipe.
Fluid flow can be classified as laminar or turbulent, primarily based on the Reynolds number. This dimensionless number reflects the relative influence of inertial to viscous...
Fluid flow can be classified as laminar or turbulent, primarily based on the Reynolds number. This dimensionless number reflects the relative influence of inertial to viscous...
2.3K
Uniform Depth Channel Flow: Problem Solving
586
To calculate the flow rate for a trapezoidal channel, first, identify the bottom width, side slope, and flow depth of the channel. The cross-sectional area (A) corresponding to the depth of flow (y), channel bottom width (B), and side slope (θ) is determined by:Next, calculate the wetted perimeter, which includes the bottom width and the sloped side lengths in contact with the water. Using the values of the cross-sectional area and the wetted perimeter, determine the hydraulic radius by...
586
Ostwald’s Dilution Law
50
Consider a binary electrolyte AB with a concentration ‘c’ that reversibly dissociates into its constituent ions. The degree of this dissociation is represented by ⍺. This means that the equilibrium concentration of each ionic species can be expressed as ⍺c. As well as this, the fraction of the electrolyte that remains undissociated at equilibrium is given by (1−⍺). The corresponding equilibrium concentration for this undissociated portion is then calculated...
50


