Related Experiment Video
Updated: May 22, 2026

06:53
Photoelectron Imaging of Anions Illustrated by 310 Nm Detachment of F−
Published on: July 27, 2018
Energy versus angular momentum in black hole binaries
Thibault Damour1, Alessandro Nagar, Denis Pollney
1Institut des Hautes Etudes Scientifiques, 91440 Bures-sur-Yvette, France.
Physical Review Letters
|May 1, 2012
Summary
The binding energy (E) and angular momentum (j) relation accurately diagnoses black-hole binary dynamics. The effective one body formalism closely matches numerical relativity simulations, unlike post-Newtonian expansions.
Area of Science:
- Astrophysics
- General Relativity
- Computational Physics
Background:
- Black-hole binaries are key systems for testing general relativity.
- Understanding their dynamics requires accurate theoretical models.
Purpose of the Study:
- To compute the gauge-invariant binding energy (E) versus angular momentum (j) relation for black-hole binaries.
- To assess the accuracy of analytic approximation schemes against numerical relativity.
Main Methods:
- Performed accurate numerical-relativity simulations for nonspinning black-hole binaries with mass ratios 1:1, 2:1, and 3:1.
- Computed the E(j) relation from simulation data.
- Compared numerical relativity results (E(NR)(j)) with analytic predictions (e.g., post-Newtonian, effective one body).
Main Results:
- The E(j) relation serves as a precise diagnostic for black-hole binary dynamics in the highly relativistic regime.
- Post-Newtonian expansions show significant deviations from numerical relativity results.
- The effective one body formalism accurately predicts the E(NR)(j) curve without numerical relativity calibration.
Conclusions:
- The effective one body formalism provides a highly accurate description of black-hole binary dynamics.
- Numerical relativity simulations are crucial for validating and improving analytic models in strong gravity regimes.
Related Concept Videos
Conservation of Angular Momentum: Application
A system's total angular momentum remains constant if the net external torque acting on the system is zero. Examples of such systems include a freely spinning bicycle tire that slows over time due to torque arising from friction, or the slowing of Earth's rotation over millions of years due to frictional forces exerted on tidal deformations. However in the absence of a net external torque, the angular momentum remains conserved. The conservation of angular momentum principle requires a change...
Angular Momentum: Single Particle
Angular momentum is directed perpendicular to the plane of the rotation, and its magnitude depends on the choice of the origin. The perpendicular vector joining the linear momentum vector of an object to the origin is called the “lever arm.” If the lever arm and linear momentum are collinear, then the magnitude of the angular momentum is zero. Therefore, in this case, the object rotates about the origin such that it lies on the rim of the circumference defined by the lever arm magnitude.
The...
The...
Conservation of Angular Momentum
A system's total angular momentum remains constant if the net external torque acting on the system is zero. Considering a system that consists of n tiny particles, the angular momentum of any tiny particle may change, but the system's total angular momentum would remain constant. The principle of conservation of angular momentum only considers the net external torque acting on the system. While there are internal forces exerted by different particles within the system that also produce internal...
Angular Momentum
Angular momentum characterizes an object's rotational motion and is defined as the moment of its linear momentum about a specified point O. When a particle moves along a curved path in the x-y plane, the scalar formulation calculates the magnitude of its angular momentum, utilizing the moment arm (d), representing the perpendicular distance from point O to the line of action of the linear momentum. Despite being scalar in formulation, angular momentum is inherently a vector quantity. Its...
Angular Momentum: Rigid Body
The total angular momentum of a rigid body can be calculated using the summation of the angular momentum of all the tiny particles rotating in the same plane. Considering all the tiny particles rotating in the x-y plane, the direction of angular momentum of all such particles and that of the rigid body would be perpendicular to the plane of the rotation along the z-axis.
This calculation can get complicated when tiny particles within the rigid body are not rotating in the same plane but have...
This calculation can get complicated when tiny particles within the rigid body are not rotating in the same plane but have...
Angular Momentum about an Arbitrary Axis
Imagine a rigid body with a mass denoted as 'm', which has its center of mass at point G and is rotating around an inertial reference frame. The angular momentum at an arbitrary point P can be calculated by taking the cross product of the position vector and linear momentum vector for each individual mass element.
The velocity of a mass element comprises its translational velocity and the relative velocity instigated by the body's rotation. Substituting the velocity equation into the angular...
The velocity of a mass element comprises its translational velocity and the relative velocity instigated by the body's rotation. Substituting the velocity equation into the angular...

