Related Experiment Video
Updated: Feb 5, 2026

09:56
Direct Force Measurements of Subcellular Mechanics in Confinement using Optical Tweezers
Published on: August 31, 2021
5.5K
Strong optical force and its confinement applications based on heterogeneous phosphorene pairs
Optics Express
|September 7, 2018
Summary
Face-to-face phosphorene pairs exhibit strong plasmonic properties due to anisotropic dispersion. Symmetric plasmonic modes offer enhanced optical constraints and gradient forces, enabling ultra-small phase shifter devices.
Area of Science:
- Condensed matter physics
- Nanophotonics
- Materials science
Background:
- Phosphorene, a 2D material, exhibits strong anisotropic optical properties.
- Plasmonic properties are crucial for light-matter interactions in nanophotonic devices.
Purpose of the Study:
- To investigate the plasmonic properties of face-to-face phosphorene pairs.
- To analyze optical constraints and gradient forces in these systems.
- To propose phosphorene-based photonic devices for applications like phase shifting.
Main Methods:
- Theoretical study of plasmonic modes in face-to-face phosphorene.
- Analysis of optical constraints and gradient forces based on anisotropic dispersion.
- Device design for an ultra-small phase shifter.
Main Results:
- Symmetric and anti-symmetric plasmonic modes arise from phosphorene's anisotropic dispersion.
- Symmetric modes demonstrate significantly stronger optical constraints and larger gradient forces than anti-symmetric modes.
- An optical constraint of up to 96% was achieved for the symmetric mode with specific layer orientations.
Conclusions:
- Face-to-face phosphorene pairs possess tunable plasmonic properties.
- The strong optical effects in symmetric modes pave the way for advanced nanophotonic applications.
- Proposed phosphorene-based devices offer potential for miniaturized photonic circuits.
Related Concept Videos
Titration Calculations: Strong Acid - Strong Base
34.0K
Calculating pH for Titration Solutions: Strong Acid/Strong Base
A titration is carried out for 25.00 mL of 0.100 M HCl (strong acid) with 0.100 M of a strong base NaOH. The pH at different volumes of added base solution can be calculated as follows:
(a) Titrant volume = 0 mL. The solution pH is due to the acid ionization of HCl. Because this is a strong acid, the ionization is complete and the hydronium ion molarity is 0.100 M. The pH of the solution is then:
A titration is carried out for 25.00 mL of 0.100 M HCl (strong acid) with 0.100 M of a strong base NaOH. The pH at different volumes of added base solution can be calculated as follows:
(a) Titrant volume = 0 mL. The solution pH is due to the acid ionization of HCl. Because this is a strong acid, the ionization is complete and the hydronium ion molarity is 0.100 M. The pH of the solution is then:
34.0K
Strong Acid and Base Solutions
35.8K
A strong acid is a compound that dissociates completely in an aqueous solution and produces a concentration of hydronium ions equal to the initial concentration of acid. For example, 0.20 M hydrobromic acid will dissociate completely in water and produces 0.20 M of hydronium ions and 0.20 M of bromide ions.
35.8K
DNA Base Pairing
33.3K
Erwin Chargaff’s rules on DNA equivalence paved the way for the discovery of base pairing in DNA. Chargaff’s rules state that in a double-stranded DNA molecule,
33.3K
DNA Base Pairing
32.7K
32.7K
Titration of a Strong Acid with a Strong Base
10.5K
During the titration of a strong acid with a strong base, pH calculations are primarily based on the concentration of residual hydronium or hydroxide ions. Initially, a strong acid like hydrochloric acid fully dissociates, creating hydronium and chloride ions, resulting in a low pH. The addition of a strong base like sodium hydroxide alters the concentration of hydronium ions by neutralizing them. As more base is added, the pH gradually increases. At the equivalence point, all hydronium ions...
10.5K
Titration Calculations: Weak Acid - Strong Base
49.3K
Calculating pH for Titration Solutions: Weak Acid/Strong Base
For the titration of 25.00 mL of 0.100 M CH3CO2H with 0.100 M NaOH, the reaction can be represented as:
For the titration of 25.00 mL of 0.100 M CH3CO2H with 0.100 M NaOH, the reaction can be represented as:
49.3K

