Light-Induced Palladium(IV)-Carbon Bond Homolysis
Linda De Marchi1, Maxime Tricoire1, Luca Demonti1
1LCM, CNRS, École Polytechnique, Institut Polytechnique de Paris, Route de Saclay, Palaiseau 91120, France.
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Palladium chemistry has been widely studied since the 1950s, particularly for cross-coupling reactions. It facilitates breaking C-X bonds through oxidative addition and forming C-C bonds through reductive elimination. These 2 electrons' elementary steps are the key features to construct highly elaborated molecules and explain their exceptional versatility. While Pd(0)/Pd(II) catalytic cycles are well understood, the behavior of Pd(IV) alkyl complexes is less studied, particularly due to their instability. Here, we report the synthesis and characterization by X-ray diffraction, solid-state magnetism, and 1H NMR of several Pd(Alkyl)4 fragments, which demonstrate unusual stability thanks to a Cp*2Yb(bipym) fragment (Cp* is for pentamethylcyclopentadienyl and bipym for 2,2'bipyrimidine). As such, the Cp*2Yb(bipym)Pd(Me)3(R) (R = Me, 3Me; Et, 3Et) complexes have a room temperature half-life of more than 17 h, while the one-electron reduction of 3Me leads to a Pd(Me)4 fragment, 3@crypt, which does not degrade over time. This unusual stability allowed us to study the original reactivities of these Pd(Alkyl)4 fragments other than classical reductive elimination. Thus, we report the first light-induced Pd(IV)-C bond homolysis, which leads to the formation of alkyl radicals. The Cp*2Yb(bipym)PdMe4 complex, 3Me, reacts under irradiation at 370 nm to form the Cp*2Yb(4Me,4H-bipym)PdMe4, 4, and the Cp*2Yb(4Me,4H-bipym)PdMe2, 5, in which the methyl radical couples with the bipym radical. The mechanism of this peculiar reaction has been determined by DFT. Similar reactivity with 3@crypt leads to the formation of a free methyl radical, as shown by EPR reaction trapping.
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