Related Experiment Video
Updated: Jan 13, 2026

Preparation of 6-aminocyclohepta-2,4-dien-1-one Derivatives via Tricarbonyltroponeiron
Published on: August 12, 2019
Base-dependent divergent α-cyanation and pyridylation of tertiary amines with cyanoaromatics
Kai Ge1, Yezhe Zhao1, Haowen Dang2
1Key Laboratory of Pollution Exposure and Health Intervention of Zhejiang Province, College of Biology and Environmental Engineering, Zhejiang Shuren University, Hangzhou 310015, P. R. China. shenjiabinhznu@163.com.
Abstract:
Divergent synthesis has emerged as a powerful and economical approach in synthetic chemistry. Herein, we show a base-dependent divergent photochemical C-C coupling reaction of tertiary amines with cyanoaromatics. Remarkably, by simply adjusting the type of base, we can selectively carry out α-cyanation and pyridylation of tertiary amines.
Related Concept Videos
Preparation of 1° Amines: Hofmann and Curtius Rearrangement Overview
Preparation of 1° Amines: Azide Synthesis
Azide ions act as good nucleophiles and react with unhindered alkyl halides to form alkyl azides. Alkyl azides do not participate in further nucleophilic substitution reactions, thereby eliminating the chances of polyalkylated products. Alkyl azides are reduced by hydride-based reducing agents, like lithium aluminum...
Preparation of Amines: Reductive Amination of Aldehydes and Ketones
Preparation of 1° Amines: Gabriel Synthesis
Strong bases like NaOH or KOH deprotonate the phthalimide to form the corresponding anion, which acts as a nucleophile. Further, the anion attacks an...
Preparation of 1° Amines: Hofmann and Curtius Rearrangement Mechanism
Preparation of Amines: Alkylation of Ammonia and Amines
Each alkylation step makes the nitrogen center more nucleophilic, which triggers successive alkylations until a quaternary ammonium salt is formed. Considering...
![[DPEPhosbcpCu]PF6: A General and Broadly Applicable Copper-Based Photoredox Catalyst](/_next/image?url=https%3A%2F%2Fcloudfront.jove.com%2FCDNSource%2Fteasers%2F59739.jpg&w=3840&q=50)
