对外骨轨迹的优化,以尽量减少人类关节扭矩.
概括
这项研究为下肢外骨提供了一个优化的轨迹,以减少人类在行走过程中的努力. 这种新的方法准确地预测了人类的运动,并显著降低了关节扭矩,提高了能源效率.
科学领域:
- 机器人技术 机器人技术 机器人技术
- 生物力学 生物力学
- 人与机器人的交互
背景情况:
- 外骨架机器人需要精确的动力学指导才能有效运行.
- 减少人类的能量消耗是外骨设计的一个关键目标.
研究的目的:
- 为下肢外骨架开发一种最佳轨迹生成方法.
- 为了最大限度地减少人类关节的扭矩,提高行走效率.
主要方法:
- 使用邻近场优化 (NFO) 计算的人类关节角度.
- 用七个环节的人类外骨架模型进行反向动态分析.
- 背向传播神经网络 (BPNN) 用于加速分析.
- 福里埃数列扰动和NFO用于轨迹优化.
主要成果:
- 在预测人类轨迹 (RMSE < 5 mm) 和地面反应力 (RMSE < 3 kN) 方面取得了高准确性.
- 生成的轨迹保留了个人的步行模式,并预测了运动 (平均领先值为4.6%).
- 在各种步态阶段显著降低了关节扭矩.
结论:
- 拟议的方法为下肢外骨架提供了准确和高效的轨迹生成.
- 这种方法适用于计算应用和设计节能辅助设备.
- 贡献了对人类外骨架相互作用动态的宝贵见解.
相关概念视频
Torque Free Motion
444
The torque-free motion refers to the movement of a rigid body in space when no external torques are acting upon it. This type of motion can be observed in environments where there are no external forces or frictions, like in outer space. For example, a rotation of Mars in space is a torque-free motion. Mars is an axisymmetric object, meaning it has an axis of symmetry along which it rotates, designated as the z-axis. The rotating frame of reference is defined such that the center of mass of...
444
Kinematic Equations: Problem Solving
11.8K
When analyzing one-dimensional motion with constant acceleration, the problem-solving strategy involves identifying the known quantities and choosing the appropriate kinematic equations to solve for the unknowns. Either one or two kinematic equations are needed to solve for the unknowns, depending on the known and unknown quantities. Generally, the number of equations required is the same as the number of unknown quantities in the given example. Two-body pursuit problems always require two...
11.8K
Development of the Limb Synovial Joints
1.3K
Joints form during embryonic development in conjunction with the formation and growth of the associated bones. The embryonic tissue that gives rise to all bones, cartilage, and connective tissues of the body is called mesenchyme.
The mesenchymal stem cells differentiate into chondrocytes that form the hyaline cartilage, and later the cartilaginous model of the bone. This model further transforms into a bone. This process is known as endochondral ossification.
During development, the limbs...
The mesenchymal stem cells differentiate into chondrocytes that form the hyaline cartilage, and later the cartilaginous model of the bone. This model further transforms into a bone. This process is known as endochondral ossification.
During development, the limbs...
1.3K
Kinematic Equations - III
7.4K
The first two kinematic equations have time as a variable, but the third kinematic equation is independent of time. This equation expresses final velocity as a function of the acceleration and distance over which it acts. The fourth kinematic equation does not have an acceleration term and provides the final position of the object at time t in terms of the initial and final velocities. This equation is useful when the value of the constant acceleration is unknown.
Using the kinematic equations,...
Using the kinematic equations,...
7.4K
Work and Energy for Variable Forces
3.3K
When an object is acted upon by a variable force, the amount of work done and the change in energy of the object can be more complex to calculate compared to when a constant force is applied. Work is the product of force and displacement, while energy is the capacity of a system to do work. When a constant force is applied to an object, the work done can be calculated as the product of the force and the distance moved in the direction of the force. However, when a variable force is applied, the...
3.3K
Kinematic Equations - II
9.2K
The second kinematic equation expresses the final position of an object in terms of its initial position, the distance traveled with the initial constant velocity, and the distance traveled due to a change in velocity. Similar to the first kinematic equation, this equation is also only valid when the acceleration is constant throughout the motion of an object.
Suppose a car merges into freeway traffic on a 200 m long ramp. If its initial velocity is 10 m/s and it accelerates at 2 m/s2, then the...
Suppose a car merges into freeway traffic on a 200 m long ramp. If its initial velocity is 10 m/s and it accelerates at 2 m/s2, then the...
9.2K


