在化物中降低高温超导的稳定压力的前景
Qiwen Jiang1, Ling Chen1, Mingyang Du2
1Key Laboratory of Material Simulation Methods & Software of Ministry of Education and State Key Laboratory of Superhard Materials, College of Physics, Jilin University, Changchun 130012, People's Republic of China.
概括
研究人员正在探索化物超导体,如硫化 (H3S),旨在在环境压力下实现室温超导. 目前的战略重点是了解电子特性和稳定性,以减少压力要求.
科学领域:
- 材料科学 材料科学 材料科学
- 凝聚物质物理学 凝聚物质物理学
- 化学 化学 化学
背景情况:
- 硫化 (H3S) 的发现激起了对化超导体的重大兴趣.
- 几十年的研究集中在在室温和环境压力下实现化物中的超导性.
研究的目的:
- 提供对当前化物超导体研究战略和进展的全面审查.
- 提供关于降低化物中高温超导性所需的压力的见解.
- 确定关键的理论和实验挑战和机会.
主要方法:
- 综述化物材料的理论预测和实验合成.
- 分析电子特性,原子聚合和稳定机制.
- 评估当前的研究格局和未来的方向.
主要成果:
- 在理解化物超导体方面取得了重大进展.
- 在基超导体中,高临界温度仍然需要高压.
- 正在研究降低稳定压力的策略.
结论:
- 化物在环境压力下仍然是室温超导体的有希望的候选者.
- 需要进一步的理论和实验努力来克服当前的挑战.
- 降低压力要求对于实际应用至关重要.
更多相关视频
11:50Metal-silicate Partitioning at High Pressure and Temperature: Experimental Methods and a Protocol to Suppress Highly Siderophile Element Inclusions
Published on: June 13, 2015
12.5K
11:17Spark Plasma Sintering Apparatus Used for the Formation of Strontium Titanate Bicrystals
Published on: February 9, 2017
9.8K
相关概念视频
Superconductor
1.1K
A substance that reaches superconductivity, a state in which magnetic fields cannot penetrate, and there is no electrical resistance, is referred to as a superconductor. In 1911, Heike Kamerlingh Onnes of Leiden University, a Dutch physicist, observed a relation between the temperature and the resistance of the element mercury. The mercury sample was then cooled in liquid helium to study the linear dependence of resistance on temperature. It was observed that, as the temperature decreased, the...
1.1K
Acid Halides to Alcohols: LiAlH4 Reduction
2.7K
Acid halides are reduced to alcohols in the presence of a strong reducing agent like lithium aluminum hydride.
The mechanism proceeds in three steps. First, the nucleophilic hydride ion attacks the carbonyl carbon of the acid halide to form a tetrahedral intermediate. Next, the carbonyl group is re-formed, and the halide ion departs as a leaving group, generating an aldehyde. A second nucleophilic attack by the hydride yields an alkoxide ion, which, upon protonation, gives a primary alcohol as...
The mechanism proceeds in three steps. First, the nucleophilic hydride ion attacks the carbonyl carbon of the acid halide to form a tetrahedral intermediate. Next, the carbonyl group is re-formed, and the halide ion departs as a leaving group, generating an aldehyde. A second nucleophilic attack by the hydride yields an alkoxide ion, which, upon protonation, gives a primary alcohol as...
2.7K
