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Updated: Dec 31, 2025

Preparation and Use of Carbonyl-decorated Carbenes in the Activation of White Phosphorus
Published on: October 3, 2014
Why do silanes reduce electron-rich phosphine oxides faster than electron-poor phosphine oxides?
Alicia M Kirk1, Christopher J O'Brien, Elizabeth H Krenske
1School of Chemistry and Molecular Biosciences, The University of Queensland, St Lucia, QLD 4072, Australia. e.krenske@uq.edu.au.
Abstract:
Organophosphine-mediated reactions that generate P[double bond, length as m-dash]O-bonded byproducts can be transformed into catalytic processes by reducing the R3P[double bond, length as m-dash]O byproduct back to PR3in situ with a silane. DFT calculations explain why the most readily reduced phosphine oxides are those incorporating electron-rich (e.g. alkyl) substituents rather than electron-deficient (e.g. aryl) substituents.
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